Put, log(t+1+t2)=z
⇒(t+1+t2)1(1+21+t22t)dt=dz
⇒(t+1+t2)(t+1+t2)1+t21dt=dz
⇒1+t21dt=dz
∴I=∫zdz=2z2+c=21[log(t+1+t2)]2+c, where c is the constant of integration.
∴g(t)=log(t+1+t2)
⇒g(2)=log(2+1+4)
Hence, log(2+5), is the answer.
JEE Main 2015 — Mathematics Calculus
If ∫1+t2log(t+1+t2)dt=21(g(t))2+c, where c is a constant, then g(2), is equal to
Held on 11 Apr 2015 · Verified 6 Jul 2026.
51log(2+5)
2log(2+5)
log(2+5)
21log(2+5)
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