(x+2)dxdy=x2+4x+4−13
dxdy=(x+2)(x+2)2−(x+2)13
dy=((x+2)−x+213)dx
y=2x2+2x−13loge∣(x+2)∣+C
If x=0 then y=0
0=0+0−13log∣2∣+C
C=13log(2)
If x=−4, then y
y=216−8−13log∣−2∣+13log∣2∣
y=0
Hence, answer is 0.
JEE Main 2015 — Mathematics Calculus
If y(x) is the solution of the differential equation (x+2)dxdy=x2+4x−9,x=−2 and y(0)=0, then y(−4) is equal to
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