f(x)={xsin(x1),0,x=0x=0 and g(x)=xf(x) For f(x)LHL=h→0−lim{−hsin(−h1)} =0× a finite quantity between −1 and 1 =0 RHL=h→0+limhsinh1=0 Also, f(0)=0 Thus LHL=RHL=f(0) ∴f(x) is continuous at x=0 g(x)={x2sinx1,0,x=0x=0 For g(x) LHL=h→0−lim{−h2sin(h1)} =02× a finite quantity between −1 and 1=0 RHL =h→0+limh2sin(h1)=0 Also g(0)=0 ∴g(x) is continuous at x=0