Since f′(x)>0 and g′(x)<0, therefore f(x) is increasing function and g(x) is decreasing function. ⇒f(x+1)>f(x) and g(x+1)<g(x) ⇒g[f(x+1)]<g[f(x)] and f[g(x+ 1) ]<f[g(x)] Hence option (b) is correct.
JEE Main 2014 — Mathematics Calculus
Let f and g be two differentiable functions on R such that f′(x)>0 and g′(x)<0 for all x∈R. Then for all x :
Held on 12 Apr 2014 · Verified 6 Jul 2026.
f(g(x))>f(g(x−1))
f(g(x))>f(g(x+1))
g(f(x))>g(f(x−1))
g(f(x))<g(f(x+1))
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