y=∣cosx−sinx∣ 
Required area =2∫0π/4(cosx−sinx)dx=2[sinx+cosx00π/4]=2[22−1]=(22−2) sq. units
JEE Main 2013 — Mathematics Calculus
The area under the curve y=∣cosx−sinx∣, 0≤x≤2π, and above x-axis is :
Held on 23 Apr 2013 · Verified 6 Jul 2026.
22
22−2
22+2
0
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