Required area =∫y=149ydy=31∫y=14y1/2dy=31×32(y3/2)14=92[(41/2)3−(11/2)3]=92[8−1] =92×7=914 sq. units.
JEE Main 2013 — Mathematics Calculus
The area of the region (in sq. units), in the first quadrant bounded by the parabola y=9x2 and the lines x=0,y=1 and y=4, is :
Held on 22 Apr 2013 · Verified 6 Jul 2026.
7/9
14/3
7/3
14/9
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