∫x5f(x3)dx =∫x3.x2f(x3)dx
Applying integration by parts, we get
=x3∫x2f(x3)dx−∫dxd(x3)∫x2f(x3)dx
=31x3ψ(x3)−∫x2ψ(x3)dx+c, where c is the constant of integration.
JEE Main 2013 — Mathematics Calculus
If ∫f(x)dx=ψ(x), then ∫x5f(x3)dx, is equal to
Held on 7 Apr 2013 · Verified 6 Jul 2026.
31x3ψ(x3)−∫x2ψ(x3)dx+c
31[x3ψ(x3)−∫x3ψ(x3)dx]+c
31[x3ψ(x3)−∫x2ψ(x3)dx]+c
31x3ψ(x3)−3∫x3ψ(x3)dx+c
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