Let I=∫x2+1x2−x+1⋅ecot−1xdx Put x=cott⇒−cosec2tdt=dx Now, 1+cot2t=cosec2t ∴ I=∫(1+cot2t)et(cot2t−cott+1)(−cosec2t)dt ⇒A(x)=−∫et(cosec2t−cott)dt=∫et(cott−cosec2t)dt=etcott+C=ecot−1x(x)+C≡A(x)⋅ecot−1x+C=x
If ∫ x^2-x+1 x^2+1 e^cot ^-1 x d x=A(x) e^cot ^-1 x+C, then A(x) is equal to :
JEE Main 2013 — Mathematics Calculus
If ∫x2+1x2−x+1ecot−1xdx=A(x)ecot−1x+C, then A(x) is equal to :
Held on 22 Apr 2013 · Verified 6 Jul 2026.
Options
- A
−x
- B
x
- C
1−x
- D
1+x
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