Let f(x)=[x]+∣1−x∣,−1≤x≤3 where [x]= greatest integer function. f is not continuous at x=0,1,2,3 But in statement-2 f(x) is continuous at x=3. Hence, statement-1 is true and 2 is false.
JEE Main 2013 — Mathematics Calculus
Consider the function : f(x)=[x]+∣1−x∣,−1≤x≤3 where [x] is the greatest integer function. Statement 1: f is not continuous at x=0,1,2 and 3 Statement 2:f(x)= =−x,1−x,1+x,2+x,−1≤x<00≤x<11≤x<22≤x≤3
Held on 25 Apr 2013 · Verified 6 Jul 2026.
Statement 1 is true; Statement 2 is false,
Statement 1 is true; Statement 2 is true; Statement 2 is not correct explanation for Statement 1.
Statement 1 is true; Statement 2 is true; Statement It is a correct explanation for Statement 1.
Statement 1 is false; Statement 2 is true.
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