Volume of sphere V=34πr3 dtd V=34⋅π⋅3r2⋅dtdr 35=4πr2⋅dtdr or dtdr=4πr235 Surface area of sphere =S=4πr2 dtd S=4π×2r×dtdr=8πr⋅dtdr dtd S=r70 Now, diameter =14 cm,r=7 ∴dtd S=10
JEE Main 2013 — Mathematics Calculus
A spherical balloon is being inflated at the rate of 35cc/min. The rate of increase in the surface area (in cm2/min.) of the balloon when its diameter is 14 cm, is :
Held on 25 Apr 2013 · Verified 6 Jul 2026.
10
10
100
1010
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The value of $\int_{-\pi / 6}^{\pi / 6}\left(\frac{\pi+4 x^{11}}{1-\sin (|x|+\pi / 6)}\right) d x$ is equal to:
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