
Area of circle =π(2)2=2π Area of OCADO=2{ Area of OCAO}=2 area of OCB+ area of BCA}=2∫01ypdx+2∫12ycdx where yp=x and yc=2−x2∴ Required Area =2∫x1dx+2∫022−x2dx=2[32⋅1−0]+2[2x2−x2+sin−12x]12 =34+2{2π−4π−21}=34+2{4π−21}=63π+2 Bigger area =2π−63π+2=69π−2∴ Required Ratio =3π+29π−2 i.e., 9π−2:3π+2