Let f′(x)f′(x)f′(1)=3x10−7x8+5x6−21x3+3x2−7=30x9−56x7+30x5−63x2+6x=30−56+30−63+6=66−63−56=−53 Consider α→0limα3+3αf(1−α)−f(1)=α→0lim3α2+3f′(1−α)(−1)−0 (By using L'hospital rule) =3(0)2+3f′(1−0)(−1)=3−f′(1)=353
If f(x)=3x10−7x8+5x6−21x3+3x2−7, then α→0limα3+3αf(1−α)−f(1) is
Held on 19 May 2012 · Verified 6 Jul 2026.
−353
353
−355
355
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