Let A=πr2 be area of metalic circular plate of r=50 cm. Also, given dtdr=1 mm=101 cm ∴A=πr2⇒dtdA=2πrdtdr=2π⋅50⋅101=10π Hence, area of plate increases in 10πcm2/ hour.
If a metallic circular plate of radius 50 ~cm is heated so that its radius increases at the rate of 1 ~mm per hour, then the rate at which, the area…
JEE Main 2012 — Mathematics Calculus
If a metallic circular plate of radius 50 cm is heated so that its radius increases at the rate of 1 mm per hour, then the rate at which, the area of the plate increases (in cm2/ hour) is
Held on 26 May 2012 · Verified 6 Jul 2026.
Options
- A
5π
- B
10π
- C
100π
- D
50π
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