f′(x)=xsinx Given x∈(0,25π) f′(x) changes sign from +ve to -ve at π f′(x) changes sign from -ve to +ve at 2π f has local max at π, local min at 2π
JEE Main 2011 — Mathematics Calculus
For x∈(0,25π), define f(x)=∫0xtsintdt. Then f has
Held on 30 Apr 2011 · Verified 6 Jul 2026.
local minimum at π and 2π
local minimum at π and local maximum at 2π
local maximum at π and local minimum at 2π
local maximum at π and 2π
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