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Let f: R → R be a function defined by f(x)= Min x+1,|x|+1. Then which of the following is true?

JEE Main 2007 — Mathematics Calculus

2007mcqeasy

Let f:R→Rf: R \rightarrow Rf:R→R be a function defined by f(x)=Min⁡{x+1,∣x∣+1}f(x)=\operatorname{Min}\{x+1,|x|+1\}f(x)=Min{x+1,∣x∣+1}. Then which of the following is true?

Official previous-year question

Held on 30 Apr 2007 · Verified 6 Jul 2026.

Options

  1. A

    f(x)≥1f(x) \geq 1f(x)≥1 for all x∈Rx \in Rx∈R

  2. B

    f(x)f(x)f(x) is not differentiable at x=1x=1x=1

  3. C

    f(x)f(x)f(x) is differentiable everywhere

  4. D

    f(x)f(x)f(x) is not differentiable at x=0x=0x=0

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