y2=2c(x+c).....(i)2yy′=2c⋅1 or yy′=c....(ii)⇒y2=2yy′(x+yy′) [on putting value of c from (ii) in (i)] On simplifying, we get (y−2xy′)2=4yy′3.....(iii) Hence equation (iii) is of order 1 and degree 3.
JEE Main 2005 — Mathematics Calculus
The differential equation representing the family of curves y2=2c(x+c), where c >0, is a parameter, is of order and degree as follows:
Held on 30 Apr 2005 · Verified 6 Jul 2026.
order 1 , degree 2
order 1, degree 1
order 1, degree 3
order 2, degree 2
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