(1−x)1/2[1+23x+23(23−1)x2−1−3(21x)−3(2)(21x)2]=(1−x)1/2[−83x2]=−83x2
JEE Main 2005 — Mathematics Calculus
If x is so small that x3 and higher powers of x may be neglected, then (1−x)1/2(1+x)3/2−(1+21x)3
Held on 30 Apr 2005 · Verified 6 Jul 2026.
1−83x2
3x+83x2
−83x2
2x−83x2
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