
A=∫−10{(3+x)−(−x+1)}dx+∫01{(3−x)−(−x+1)}dx+∫12{(3−x)−(−x−1)}dx =∫−10(2+2x)dx+∫012dx+∫12(4−2x)dx =[2x−x2]−10+[2x]01+[4x−x2]12 =0−(−2+1)+(2−0)+(8−4)−(4−1) =1+2+4−3=4 sq. units
JEE Main 2003 — Mathematics Calculus
The area of the region bounded by the curves y=∣x−1∣ and y=3−∣x∣ is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
6 sq. units
2 sq. units
3 sq. units
4 sq. units
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