Let t=∣x−1∣ where t≥0.
Equation becomes t2−5t+6=0.
(t−2)(t−3)=0 gives t=2 or t=3.
For ∣x−1∣=2: x=3 or x=−1.
For ∣x−1∣=3: x=4 or x=−2.
Sum of roots =3+(−1)+4+(−2)=4.
JEE Main 2026 — Mathematics Algebra
The sum of all the roots of the equation (x−1)2−5∣x−1∣+6=0, is :
Held on 21 Jan 2026 · Verified 6 Jul 2026.
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