Distributing 16 identical oranges to 4 children with each getting at least 1.
Let xi≥1 for i=1,2,3,4 and x1+x2+x3+x4=16.
Substituting yi=xi−1≥0: y1+y2+y3+y4=12.
By stars and bars, number of ways =(312+3)=(315)=615×14×13=455.
JEE Main 2026 — Mathematics Algebra
The number of ways, in which 16 oranges can be distributed to four children such that each child gets at least one orange, is
Held on 23 Jan 2026 · Verified 6 Jul 2026.
455
429
403
384
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