We need 4x2+y2<52 with x,y∈Z. This requires x2<13, so x∈{−3,−2,−1,0,1,2,3}.
x=0: y2<52⇒y∈{−7,...,7} → 15 values
x=±1: y2<48⇒∣y∣≤6 → 13 each → 26 values
x=±2: y2<36⇒∣y∣≤5 → 11 each → 22 values
x=±3: y2<16⇒∣y∣≤3 → 7 each → 14 values
Total =15+26+22+14=77