The general term in the expansion of (2x2+x1)10 is given by:
Tr+1=10Cr(2x2)10−r(x1)r
Tr+1=10Cr210−rx20−2rx−r
Tr+1=10Cr210−rx20−3r
For the coefficient of x2, we equate the power of x to 2:
20−3r=2
3r=18⇒r=6
Substituting r=6 in the coefficient part, we get:
Coefficient =10C6210−6
=10C424
=4×3×2×110×9×8×7×16
=210×16
=3360
Answer: 3360