m=i=1∑9i2=69⋅10⋅19=285, so 19m=15.
The equation becomes 3f(x)+2f(x15)=5x ...(i)
Replace x by x15: 3f(x15)+2f(x)=x75 ...(ii)
From 3×(i)−2×(ii): 5f(x)=15x−x150, so f(x)=3x−x30.
f(5)=15−6=9, f(2)=6−15=−9.
f(5)−f(2)=9−(−9)=18.
JEE Main 2026 — Mathematics Algebra
Let f be a function such that 3f(x)+2f(19xm)=5x,x=0, where m=i=1∑9(i)2. Then f(5)−f(2) is equal to
Held on 24 Jan 2026 · Verified 6 Jul 2026.
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