A={x:∣x2−10∣≤6}: −6≤x2−10≤6⇒4≤x2≤16, so A=[−4,−2]∪[2,4].
B={x:∣x−2∣>1}=(−∞,1)∪(3,∞).
Ac=(−∞,−4)∪(−2,2)∪(4,∞).
B−A=B∩Ac=[(−∞,1)∩Ac]∪[(3,∞)∩Ac]
=[(−∞,−4)∪(−2,1)]∪[(4,∞)]
=(−∞,−4)∪(−2,1)∪(4,∞).
Let A={x:x2−10≤6} and B={x:∣x−2∣>1}. Then
Held on 21 Jan 2026 · Verified 6 Jul 2026.
A∪B=(−∞,1]∪(2,∞)
B−A=(−∞,−4)∪(−2,1)∪(4,∞)
A−B=[2,3)
A∩ B=[−4,−2]∪[3,4]
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