Divide numerator and denominator by x18, let t=x−9+x−7+2, then dt=−(9x−10+7x−8)dx.
f(x)=t1+C=1+x2+2x9x9+C.
x→0limf(x)=0⇒C=0. f(1)=41 (verified).
f′(x)=(1+x2+2x9)29x8(1+x2+2x9)−x9(2x+18x8).
f′(1)=1636−20=1.
∣A∣=01/4α2014111=1−α2.
∣B∣=∣adj(adj A)∣=∣A∣(3−1)2=(1−α2)4=81=34.
∣1−α2∣=3⇒α2=4.