If x2+2 divides x3+ax2+bx+c, write x3+ax2+bx+c=(x2+2)(x+k).
Expanding: x3+kx2+2x+2k.
Comparing coefficients: a=k, b=2, c=2a.
Constraints: a∈N, a≤20, and c=2a≤20⇒a≤10.
So a∈{1,2,3,...,10}, giving 10 polynomials.
JEE Main 2026 — Mathematics Algebra
Let S={x3+ax2+bx+c:a,b,c∈ N and a,b,c≤20} be a set of polynomials. Then the number of polynomials in S, which are divisible by x2+2, is
Held on 28 Jan 2026 · Verified 6 Jul 2026.
10
20
6
120
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