X=∣A∣1adj(A)⋅B.
∣adj(A)∣=4(10)−2(−20)+2(10)=100, so ∣A∣2=100⇒∣A∣=±10.
adj(A)⋅B=16+0+4−20+0+104+0+6=20−1010
x+y+z=∣A∣20−10+10=±1020=±2
∣x+y+z∣=2
If X=xyz is a solution of the system of equations AX=B, where adjA=4−5120−2253 and B=402, then ∣x+y+z∣ is equal to :
Held on 22 Jan 2026 · Verified 6 Jul 2026.
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