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If α=1 and β=1+i√2, where i=√-1 are two roots of the equation x^3+ax^2+bx+c=0, a,b,c ∈ mathbbR, then ∫_-1^1(x^3+ax^2+bx+c)dx is equal to:

JEE Main 2026 — Mathematics Algebra

2026mcqmedium

If α=1\alpha=1α=1 and β=1+i2\beta=1+i\sqrt{2}β=1+i2​, where i=−1i=\sqrt{-1}i=−1​ are two roots of the equation x3+ax2+bx+c=0x^3+ax^2+bx+c=0x3+ax2+bx+c=0, a,b,c∈Ra,b,c \in \mathbb{R}a,b,c∈R, then ∫−11(x3+ax2+bx+c)dx\displaystyle \int_{-1}^{1}(x^3+ax^2+bx+c)dx∫−11​(x3+ax2+bx+c)dx is equal to:

Official previous-year question

Held on 4 Apr 2026 · Verified 6 Jul 2026.

Options

  1. A

    −2-2−2

  2. B

    −4-4−4

  3. C

    −8-8−8

  4. D

    −10-10−10

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