If 141+241+341+…..∞=90π4....(i)
β=241+441+641+…,=161[141+241+341+…..],
=161×90π4
using (ii) ________...(ii)
α=141+341+541+…..∞(141+241+341+441+541+…..)−(241+441+641+…..)
α=90π4−161×90π4[ using (i) and (ii)]
α=16×9016−1×π4=16×9015π4=96π4∴βα=16×90π496π4=9616×90=15