(x32+1−x31)(x+1)−(x−x21)(x−1)10=((x31+1)−(xx+1))10=(x31−x1)10Tr+1=10Cr(x)310−r(−1)r(x)−2r310−r−2r=0(20−2r)−3r=0r10=4⇒10C4(−1)4=210
The term independent of x in the expansion of ((x2/3+1−x1/3)(x+1)−(x−x1/2)(x+1))10,x>1 is:
Held on 2 Apr 2025 · Verified 6 Jul 2026.
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