$\begin{aligned}
& S_{11}=\frac{11}{2}(2 a+10 d)=88 \
& a+5 d=8 \
& a=8-5 \times \frac{3}{2}=\frac{1}{2}
\end{aligned}Rootsare\begin{aligned}
& \mathrm{T}{10}=\mathrm{a}+9 \mathrm{d}=\frac{1}{2}+9 \times \frac{3}{2}=14 \
& \mathrm{T}{11}=\mathrm{a}+10 \mathrm{~d}=\frac{1}{2}+10 \times \frac{3}{2}=\frac{31}{2} \
& \frac{\mathrm{p}}{3}=\mathrm{T}{10}+\mathrm{T}{11}=14+\frac{31}{2}=\frac{59}{2} \
& \mathrm{p}=\frac{177}{2} \
& \frac{\mathrm{q}}{3}=\mathrm{T}{10} \times \mathrm{T}{11}=7 \times 31=217 \
& \mathrm{q}=651 \
& \mathrm{q}-2 \mathrm{p} \
& =651-177 \
& =474
\end{aligned}$