$\begin{aligned}
& \text { General term }={ }^{\mathrm{n}} \mathrm{C}{\mathrm{r}}\left{7^{1 / 3}\right}^{\mathrm{n}-\mathrm{r}}\left(11^{1 / 12}\right)^{\mathrm{r}} \
& ={ }^{\mathrm{n}} \mathrm{C}{\mathrm{r}}{7}^{\frac{\mathrm{n}-\mathrm{r}}{3}}(11)^{\mathrm{r} / 12}
\end{aligned}Forintegralterms,rmustbemultipleof12\therefore \mathrm{r}=12 \mathrm{k}, \mathrm{k} \in \mathrm{~W}Totalvaluesofr=183Hence\max r=12(182)=2184Minvalueofn=2184$
The least value of n for which the number of integral terms in the Binomial expansion of (√[3]7+√[12]11)^ n is 183, is :
JEE Main 2025 — Mathematics Algebra
The least value of n for which the number of integral terms in the Binomial expansion of (37+1211)n is 183, is :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
Options
- A
2184
- B
2196
- C
2148
- D
2172
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