∣A∣=211C11=k=1∑2a1k⋅A1k=a11 A11+a12 A12=∣A∣=211C12=k=1∑2a1k⋅A2k=0C21=k=1∑2a2k⋅A1k=0C22=k=1∑2a2k⋅A2k=∣A∣=211C=[11/20011/2]∣C∣=41218∣C∣=242
Let A= [ a_i j ]= [ … ]. If A_i j is the cofactor of a_i j, C_i j=Σ_ k=1^2 a_i k A_j k, 1 ≤ i, j ≤ 2, and C= [ C_i j ], then 8| C| is equal to :
JEE Main 2025 — Mathematics Algebra
Let A=[aij]=[log5128log58log45log425]. If Aij is the cofactor of aij,Cij=k=1∑2aikAjk,1≤i,j≤2, and C=[Cij], then 8∣C∣ is equal to :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
Options
- A
288
- B
222
- C
242
- D
262
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