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Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x)=sec ^-1(2[x]+1) is :

JEE Main 2025 — Mathematics Algebra

2025mcqeasy

Let [x][x][x] denote the greatest integer less than or equal to xxx. Then the domain of f(x)=sec⁡−1(2[x]+1)f(x)=\sec ^{-1}(2[x]+1)f(x)=sec−1(2[x]+1) is :

Official previous-year question

Held on 28 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    (−∞,−1]∪[0,∞)(-\infty,-1] \cup[0, \infty)(−∞,−1]∪[0,∞)

  2. B

    (−∞,−1]∪[1,∞)(-\infty,-1] \cup[1, \infty)(−∞,−1]∪[1,∞)

  3. C

    (−∞,∞)(-\infty, \infty)(−∞,∞)

  4. D

    (−∞,∞)−{0}(-\infty, \infty)-\{0\}(−∞,∞)−{0}

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