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Let S= N ∪0. Define a relation R from S to R by : R= (x, y): log _ e y=x log _ e ( 2 5 ), x ∈ ~S, y ∈ R Then, the sum of all the elements in the…

JEE Main 2025 — Mathematics Algebra

2025mcqmedium

Let S=N∪{0}S=\mathbf{N} \cup\{0\}S=N∪{0}. Define a relation RRR from SSS to R\mathbf{R}R by : R={(x,y):log⁡ey=xlog⁡e(25),x∈ S,y∈R}\mathrm{R}=\left\{(x, y): \log _{\mathrm{e}} y=x \log _{\mathrm{e}}\left(\frac{2}{5}\right), x \in \mathrm{~S}, y \in \mathbf{R}\right\}R={(x,y):loge​y=xloge​(52​),x∈ S,y∈R} Then, the sum of all the elements in the range of RRR is equal to :

Official previous-year question

Held on 29 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    109\frac{10}{9}910​

  2. B

    32\frac{3}{2}23​

  3. C

    52\frac{5}{2}25​

  4. D

    53\frac{5}{3}35​

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