As a1+a5+a10+…+a2020+a2024=2233 ...(1) We know in arithmetic progression. Sum of terms equidistant from ends is equal ∴ from (1) 203 pairs a1+a2024=a5+a2020=a10+a2015=… ⇒203(a1+a2024)=2233⇒a1+a2024=11 Now i=1∑2024ai=S2024=22024[a1+a2024]=1012(11)=11132