A3−2A2−4A+4I=0A3=2A2+4A−4IA4=2A3+4A2−4A=2(2A2+4A−4I)+4A2−4AA4=8A2+4A−8IA5=8A3+4A2−8A=8(2A2+4A−4I)+4A2−8AA5=20A2+24A−32I∴α=20,β=24,γ=−32∴α+β+γ=12
Let A be a 3 × 3 real matrix such that A^2(A-2 I)- 4( ~A- I)= O, where I and O are the identity and null matrices, respectively. If A^5=α A^2+β A+γ…
JEE Main 2025 — Mathematics Algebra
Let A be a 3×3 real matrix such that A2(A−2I)− 4( A−I)=O, where I and O are the identity and null matrices, respectively. If A5=αA2+βA+γI, where α,β and γ are real constants, then α+β+γ is equal to:
Held on 2 Apr 2025 · Verified 6 Jul 2026.
Options
- A
12
- B
20
- C
76
- D
4
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