A=(2)2(2)3(2)4(2)3(2)4(2)5(2)4(2)5(2)6A=2224224424428A2=221222222222412222222224 =4−−(2+4+8)−−(22+42+82)−−(4+8+16) Sum of elements of 3nd row =4(14+142+28) $\begin{aligned}
& =4(42+14 \sqrt{2}) \
& =168+56 \sqrt{2} \
& \alpha+\beta \sqrt{2} \
\therefore & \alpha+\beta=168+56=224
\end{aligned}$