k+z2+k2z=kz∣z∣2k=2k=2
point p(2,4); center (1,2)
distance from circle
(x−1)2+(y−2)2=1 is max.
if (OP+r)=1+4+1=5+1
JEE Main 2025 — Mathematics Algebra
Let z be a complex number such that ∣z∣=1. If k+z2+k2z=kz,k∈R, then the maximum distance of k+ik2 from the circle ∣z−(1+2i)∣=1 is:
Held on 2 Apr 2025 · Verified 6 Jul 2026.
5+1
2
3
3+1
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