f(g(x))=ln(2x2−2x+1x4−2x3+3x2−2x+2) Since 2x2−2x+1>0∀x∈R∵(−2)2−4(2)<0 Consider $\begin{aligned}
& x^4-2 x^3+3 x^2-2 x+2 \
& =\left(x^4-2 x^3+x^2\right)+\left(x^2-2 x+1\right)+\left(1+x^2\right) \
& =x^2(x-1)^2+(x-1)^2+\left(x^2+1\right)>0 \forall x \in \mathbb{R} \
& \Rightarrow g(x)>0 \forall x \in \mathbb{R} \
& \Rightarrow \ln f((x)), f(x)>0 \forall x \in \mathbb{R} \
& \Rightarrow x \in \mathbb{R} \text { is domain }
\end{aligned}$