f(g(x))=ln(2x2−2x+1x4−2x3+3x2−2x+2) Since 2x2−2x+1>0∀x∈R∵(−2)2−4(2)<0 Consider $\begin{aligned}
& x^4-2 x^3+3 x^2-2 x+2 \
& =\left(x^4-2 x^3+x^2\right)+\left(x^2-2 x+1\right)+\left(1+x^2\right) \
& =x^2(x-1)^2+(x-1)^2+\left(x^2+1\right)>0 \forall x \in \mathbb{R} \
& \Rightarrow g(x)>0 \forall x \in \mathbb{R} \
& \Rightarrow \ln f((x)), f(x)>0 \forall x \in \mathbb{R} \
& \Rightarrow x \in \mathbb{R} \text { is domain }
\end{aligned}$
Let f(x)=log _ e x and g(x)= x^4-2 x^3+3 x^2-2 x+2 2 x^2-2 x+1. Then the domain of f ° g is
JEE Main 2025 — Mathematics Algebra
Let f(x)=logex and g(x)=2x2−2x+1x4−2x3+3x2−2x+2. Then the domain of f∘g is
Held on 23 Jan 2025 · Verified 6 Jul 2026.
Options
- A
[0,∞)
- B
[1,∞)
- C
(0,∞)
- D
R
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Algebra in other years
More JEE Main Algebra questions
The number of elements in the set $S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}$, is :
Suppose $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in A.P. and $\mathrm{a}^{2}, 2 \mathrm{~b}^{2}, \mathrm{c}^{2}$ are in G.P. If $\mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\mathrm{a}+\mathrm{b}+\mathrm{c}=1$, then $9\left(\mathrm{a}^{2}+\mathrm{b}^{2}+\mathrm{c}^{2}\right)$ is equal to $\_\_\_\_$ .
Let $S=\left\{z \in \mathbb{C}: 4 z^{2}+\bar{z}=0\right\}$. Then $\sum_{z \in S}|z|^{2}$ is equal to:
Let $S=\{z: 3 \leqslant|2 z-3(1+i)| \leqslant 7\}$ be a set of complex numbers. Then $\min _{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to :
Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}$ and $B = [b_{ij}]$, $1 \leq i, j \leq 3$. If $B = A^{99} - I$, then the value of $\dfrac{b_{31} - b_{21}}{b_{32}}$ is :
Other Mathematics topics for JEE Main
Keep practicing Algebra
Work through every JEE Main Algebra PYQ, year by year.