Let z=x+iy
$\begin{aligned}
& A:|z-2-i|=3 \
& |(x-2)+(y-1) i|=3 \
& (x-2)^2+(y-1)^2=9 ....(1)\
& B=\operatorname{Re}(z-i z)=2 \
& \operatorname{Re}((x+y)+i(y-x))=2 \
& x+y=2....(2)
\end{aligned} .$
On solving (1) and (2) we get
$\begin{aligned}
& x=\frac{3 \pm \sqrt{17}}{2}, y=\frac{1 \mp \sqrt{17}}{2} \
& \sum_{z \in \mathrm{~s}}|z|^2=\frac{1}{4}[2 \times 26+2 \times 18] \
& \Rightarrow \frac{88}{4}=22
\end{aligned}$