$\begin{aligned}
& \left(x+\sqrt{x^3-1}\right)^5+\left(x-\sqrt{x^3-1}\right)^5 \
& -\left[{ }^5 C_0 x^5+{ }^5 C_1 x^4\left(\sqrt{x^3-1}\right)+\ldots \ldots+{ }^5 C_5\left(\sqrt{x^3-1}\right)^5\right]+ \
& {\left[{ }^5 C_0 x^5-{ }^5 C_1 x^4\left(\sqrt{x^3-1}\right)+\ldots \ldots .+{ }^{-5} C_5\left(\sqrt{x^3-1}\right)^5\right]} \
& =2\left[x^5+{ }^5 C_2 x^3\left(x^3-1\right)+{ }^5 C_4\left(x^3-1\right)^2\right] \
& =10 x^7+20 x^6+2 x^5-20 x^4-20 x^3+10 x
\end{aligned}Now\alpha=10, \beta=2, \gamma=-20, \delta=10Also,\begin{aligned}
& \left.\begin{array}{c}
10 u+2 v=18 \
-20 u+10 v=20
\end{array}\right} u=1, v=4 \
& u+v=5
\end{aligned}$
Let α, β, γ and δ be the coefficients of x^7, x^5, x^3 and x respectively in the expansion of (x+√x^3-1 )^5+ (x-√x^3-1 )^5, xgt1. If u and v satisfy…
JEE Main 2025 — Mathematics Algebra
Let α,β,γ and δ be the coefficients of x7,x5,x3 and x respectively in the expansion of (x+x3−1)5+(x−x3−1)5,x>1. If u and v satisfy the equations $\begin{aligned}
& \alpha u+\beta v=18 \
& \gamma u+\delta v=20
\end{aligned}thenu+v$ equals :
Held on 22 Jan 2025 · Verified 6 Jul 2026.
Options
- A
5
- B
3
- C
4
- D
8
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