$\begin{aligned}
& \Delta=\left|\begin{array}{ccc}
1 & 2 & -3 \
2 & \lambda & 5 \
14 & 3 & \mu
\end{array}\right|=0 \Rightarrow \lambda \mu+42 \lambda-4 \mu+107=0 \
& \Delta_1=\left|\begin{array}{ccc}
2 & 2 & -3 \
5 & \lambda & 5 \
33 & 3 & \mu
\end{array}\right|=0 \Rightarrow 2 \lambda \mu+99 \lambda-10 \mu+255=0 \
& \Delta_2=\left|\begin{array}{ccc}
1 & 2 & -3 \
2 & 5 & 5 \
14 & 33 & \mu
\end{array}\right|=0 \Rightarrow \mu=13
\end{aligned}Also,\lambda=-1Hence,\lambda+\mu=13-1=12$
If the system of equations … has infinitely many solutions, then\lambda+\mu is equal to :
JEE Main 2025 — Mathematics Algebra
If the system of equations $\begin{aligned}
& x+2 y-3 z=2 \
& 2 x+\lambda y+5 z=5 \
& 14 x+3 y+\mu z=33
\end{aligned}hasinfinitelymanysolutions,then\lambda+\mu$ is equal to :
Held on 24 Jan 2025 · Verified 6 Jul 2026.
Options
- A
13
- B
10
- C
12
- D
11
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