$\lim _{x \rightarrow 0}\left|\begin{array}{ccc}
a+\frac{\sin x}{x} & 1 & b \
a & 1+\frac{\sin x}{x} & b \
a & 1 & b+\frac{\sin x}{x}
\end{array}\right|=\lambda+\mu a+v bAt\lim x \rightarrow 0,\begin{aligned}
& f(x)=\left|\begin{array}{ccc}
a+1 & 1 & b \
a & 1+1 & b \
a & 1 & b+1
\end{array}\right|=\lambda+\mu a+v b \
& R_1 \rightarrow R_1-R_2 \
& R_2 \rightarrow R_2-R_3 \
& \left|\begin{array}{ccc}
1 & -1 & 0 \
0 & 1 & -1 \
a & 1 & b+1
\end{array}\right|=\lambda+\mu a+v b \
& \mathrm{C}_2 \rightarrow \mathrm{C}_1-\mathrm{C}_2 \
& \left|\begin{array}{ccc}
1 & 0 & 0 \
0 & 1 & -1 \
a & a+1 & b+1
\end{array}\right|=\lambda+\mu a+v b \
& a+b+2=\lambda+\mu a+v b \
& \lambda=2, \mu=1, \quad v=1 \
& (\lambda+\mu+v)=(2+1+1)^2=16
\end{aligned}$