$\begin{aligned}
& \sec ^2 x-\tan ^2 x=1 \quad(\text { on replacing } y \text { with } x) \
& \Rightarrow \text { Reflexive } \
& \sec ^2 x-\tan ^2 y=1 \
& \Rightarrow 1+\tan ^2 x+1-\sec ^2 y=1 \
& \Rightarrow \sec ^2 y-\tan ^2 x=1 \
& \Rightarrow \text { symmetric } \
& \sec ^2 x-\tan ^2 y=1 \
& \sec ^2 y-\tan ^2 z=1
\end{aligned}Addingboth\begin{aligned}
& \Rightarrow \sec ^2 x-\tan ^2 y+\sec ^2 y-\tan ^2 z=1+1 \
& \sec ^2 x+1-\tan ^2 z=2 \
& \sec ^2 x-\tan ^2 z=1 \
& \Rightarrow \text { Transitive }
\end{aligned}$ hence equivalence releation
Define a relation R on the interval [0, π 2 ) by x R y if and only if sec ^2 x-tan ^2 y=1. Then R is :
JEE Main 2025 — Mathematics Algebra
Define a relation R on the interval [0,2π) by xRy if and only if sec2x−tan2y=1. Then R is :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
Options
- A
both reflexive and transitive but not symmetric
- B
an equivalence relation
- C
reflexive but neither symmetric not transitive
- D
both reflexive and symmetric but not transitive
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Algebra in other years
More JEE Main Algebra questions
The number of elements in the set $S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}$, is :
Suppose $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in A.P. and $\mathrm{a}^{2}, 2 \mathrm{~b}^{2}, \mathrm{c}^{2}$ are in G.P. If $\mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\mathrm{a}+\mathrm{b}+\mathrm{c}=1$, then $9\left(\mathrm{a}^{2}+\mathrm{b}^{2}+\mathrm{c}^{2}\right)$ is equal to $\_\_\_\_$ .
Let $S=\left\{z \in \mathbb{C}: 4 z^{2}+\bar{z}=0\right\}$. Then $\sum_{z \in S}|z|^{2}$ is equal to:
Let $S=\{z: 3 \leqslant|2 z-3(1+i)| \leqslant 7\}$ be a set of complex numbers. Then $\min _{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to :
Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}$ and $B = [b_{ij}]$, $1 \leq i, j \leq 3$. If $B = A^{99} - I$, then the value of $\dfrac{b_{31} - b_{21}}{b_{32}}$ is :
Other Mathematics topics for JEE Main
Keep practicing Algebra
Work through every JEE Main Algebra PYQ, year by year.