$\begin{aligned}
& (428)^{2024}=(420+8)^{2024} \
& =(21 \times 20+8)^{2024} \
& =21 \mathrm{~m}+8^{2024}
\end{aligned}$
Now 82024=(82)1012 $\begin{aligned}
& =(64)^{1012} \
& =(63+1)^{1012} \
& =(21 \times 3+1)^{1012} \
& =2 \ln +1
\end{aligned}\Rightarrow$ Remainder is 1.