Case I : x≥−5 $\begin{aligned}
& x^2+5 x+2 x+12=0 \
& x^2+7 x+12=0 \
& x=-3,-4
\end{aligned}CaseII:-7 < \mathrm{x} < -5-x^2-5 x+2 x+14-2=0\begin{aligned}
& -x^2-3 x+12=0 \
& x=\frac{-3 \pm \sqrt{9+48}}{2} \
& =\frac{-3 \pm \sqrt{57}}{2} \
& x=\frac{-3-\sqrt{57}}{2}, \frac{-3+\sqrt{57}}{2} \text { (rejected) }
\end{aligned}CaseIII:\mathrm{x} \leq-7\begin{aligned}
& -x^2-5 x-2 x-14-2=0 \
& x^2+7 x+16=0 \
& D=49-64 < 0
\end{aligned}NosolutionsNo.ofsolutions=3$
The number of real solutions of the equation x|x+5|+2|x+7|-2=0 is
JEE Main 2024 — Mathematics Algebra
The number of real solutions of the equation x∣x+5∣+2∣x+7∣−2=0 is_________
Held on 5 Apr 2024 · Verified 6 Jul 2026.
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Algebra in other years
More JEE Main Algebra questions
The number of elements in the set $S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}$, is :
Suppose $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in A.P. and $\mathrm{a}^{2}, 2 \mathrm{~b}^{2}, \mathrm{c}^{2}$ are in G.P. If $\mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\mathrm{a}+\mathrm{b}+\mathrm{c}=1$, then $9\left(\mathrm{a}^{2}+\mathrm{b}^{2}+\mathrm{c}^{2}\right)$ is equal to $\_\_\_\_$ .
Let $S=\left\{z \in \mathbb{C}: 4 z^{2}+\bar{z}=0\right\}$. Then $\sum_{z \in S}|z|^{2}$ is equal to:
Let $S=\{z: 3 \leqslant|2 z-3(1+i)| \leqslant 7\}$ be a set of complex numbers. Then $\min _{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to :
Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}$ and $B = [b_{ij}]$, $1 \leq i, j \leq 3$. If $B = A^{99} - I$, then the value of $\dfrac{b_{31} - b_{21}}{b_{32}}$ is :
Other Mathematics topics for JEE Main
Keep practicing Algebra
Work through every JEE Main Algebra PYQ, year by year.