Given,
x(x2+3∣x∣+5∣x−1∣+6∣x−2∣)=0
⇒x=0orx2+3∣x∣+5∣x−1∣+6∣x−2∣=0
We know that sum of all positive terms can never be zero,
So, x2+3∣x∣+5∣x−1∣+6∣x−2∣ can never be zero for any value of x,
So there is no value of x which satisfies the above equation
Hence, only solution is x=0, i.e. number of solution is 1 .