∣x+1∣∣x+3∣−4∣x+2∣+5=0 case-1 $\begin{aligned}
& x \leq-3 \
& (x+1)(x+3)+4(x+2)+5=0 \
& x^2+4 x+3+4 x+8+5=0 \
& x^2+8 x+16=0 \
& (x+4)^2=0 \
& x=-4
\end{aligned}case−2\begin{aligned}
& -3 \leq x \leq-2 \
& -x^2-4 x-3+4 x+8+5=0 \
& -x^2+10=0 \
& x= \pm \sqrt{10}
\end{aligned}case−3\begin{aligned}
& -2 \leq x \leq-1 \
& -x^2-4 x-3-4 x-8+5=0 \
& -x^2-8 x-6=0 \
& x^2+8 x+6=0 \
& x=\frac{-8 \pm 2 \sqrt{10}}{2}=-4 \pm \sqrt{10}
\end{aligned}case−4\begin{aligned}
& x \geq-1 \
& x^2+4 x+3-4 x-8+5=0 \
& x^2=0 \
& x=0
\end{aligned}$
No. of solution =2