Given:
Out of 20 numbered lines, even numbered lines are concurrent, odd number lines are parallel.
So, the maximum number of intersection points will be given by,
N=(1→point of intersection when both lines are even)+(0→point of intersection when both lines are parallel)+(C110×C110→point of intersection when 1 odd and 1 even line meets)
⇒N=1+0+100
⇒N=101